A block of mass `2kg` is propped from a height of `40cm` on a spring where force constant is `1960Nm^(-1)` The maximum distance thought which the spring compressed by

Options

A. `5cm`
B. `15 cm`
C. `26 cm`
D. `10 cm`

Answer

D

Explanation

`mg(h + x) = (1)/(2) kx^(2)`
Here, `m = 2kg, h = 60 cm`
`k = 1960Nm^(-1)` and `g = 10ms^(-2)`
`:. 2 xx 10(0.5 + x) = (1)/(2) xx 1960x^(2)`
On solving we get `x = 10cm`