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A particle is moved from `(0,0)`to `(a,a)` under a force `bar F = (3hati + 4hatj)` and path `2is OQP`.Let `W_(1) and W_(2)` be the work by done this force in these to paths .Then .

A

`W_(1) = W_(2)`

B

`W_(1) = 2W_(2)`

C

`W_(2) = 2W_(1)`

D

`W_(2) =4 W_(1)`

Text Solution

Verified by Experts

The correct Answer is:
A

Given force is a constant force and wolt down is per independent inder a constant force Hence `W_(1) - W_(2)`
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A2Z-WORK, ENERGY, POWER AND COLLISION-Potential Energy, Conservative And Non-Conservative Forces
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