A slab `S` of mass `m` released from a height `h_(0)`, from the top of a spring of force constant `k`. The maximum compression `x` of the spring is given by the equation.

Options

A. `mg h_(0) = (1)/(2) kx^(2)`
B. `mg (h_(0) - x) = (1)/(2) kx^(2)`
C. `mg h_(0) = (1)/(2) k(h_(0) + x)^(2)`
D. `mg (h_(0) + x) = (1)/(2) kx^(2)`

Answer

D

Explanation

Equate loss of gravitational potential energy with gain of elastic potential energy.