A toy gun a spring of force constant `k`. When changed before being triggered in the upward direction, the spring is compressed by a distance `x`. If the mass of the shot is `m`, on the being triggered it will go up to a height of

Options

A. `(Kx^(2))/(8g)`
B. `(x^(2))/(8g)`
C. `(Kx^(2))/(2 mg)`
D. `(K^(2)x^(2))/(mg)`

Answer

C

Explanation

According to law of conservation of energy , elastic potential energy strod in spring = gravational potential energy acquired by shot
`(1)/(2) kx^(2) = mgh or h = (kx^(2))/(2 mg)`