The kinetic energy of partical moving along a circule of radius `R` depends upon the distance covered `S` and given by `K = aS` where `a` is a constant. The the force acting on the partical is

Options

A. `(aS)/( R)`
B. `(2aS^(2))/( R)`
C. `(aS^(2))/( R^(2))`
D. `(2aS)/( R)`

Answer

D

Explanation

Force on a partical moving on a circular path
= Contripetal force `= (mv^(2))/( R)`
`= ((1)/(2) mv^(2)) (2)/( R) = (2K)/( R) = (2 aS)(R )`