A particle of mass `m` oscillates along the horizontal diameter `AB` inside a smooth spherical shell of radius `R`. At any instant `K.E.` of the partical is `K`. Then force applied by particle on the shell at this instant is:

Options

A. `(K)/( R)`
B. `(2K)/( R)`
C. `(3K)/( R)`
D. `(K)/(2R)`

Answer

C

Explanation

`mgR sin theta = (1)/(2) mv^(2) = K`
So, `mg sin theta (K)/(R)`
`N = 3 mg sin theta = (3K)/( R)`