The frequency `(n)` of vibration of a string is given as ` n = (1)/( 2 l) sqrt((T)/(m))` , where `T` is tension and `l` is the length of vibrating string , then the dimensional formula is

The frequency (n) of vibration of a string is given as n = (1)/( 2 l) sqrt((T)/(m)) , where T is tension and l is the length of vibrating string , then the dimensional formula for m is

The frequency (n) of vibration of a string is given as n=(1)/(2l)sqrt(T/(m)), where T is tension and l is the length of vibrating string, then the dimensional formula for m is :

The frequency of vibration of string is given by v = (p)/(2 l) [(F)/(m)]^(1//2) . Here p is number of segment is the string and l is the length. The dimension formula for m will be

The frequency of vibration of string is given by v=p/(2l)[F/m]^(1//2) . Here p is number of segments in the string and l is the length. The dimensional formula for m will be

The frequency of vibration of string is given by v=p/(2l)[F/m]^(1//2) . Here p is number of segments in the string and l is the length. The dimensional formula for m will be

The mass suspended from the stretched string of a sonometer is 4 kg and the linear mass density of string 4 xx 10^(-3) kg m^(-1) . If the length of the vibrating string is 100 cm , arrange the following steps in a sequential order to find the frequency of the tuning fork used for the experiment . (A) The fundamental frequency of the vibratinng string is , n = (1)/(2l) sqrt((T)/(m)) . (B) Get the value of length of the string (l) , and linear mass density (m) of the string from the data in the problem . (C) Calculate the tension in the string using , T = mg . (D) Substitute the appropriate values in n = (1)/(2l) sqrt((T)/(m)) and find the value of 'n' .

The frequency of vibration (v) of a string may depend upon length (I) of the string, tension (T) in the string and mass per unit length (m) of the string. Using the method of dimensions, derive the formula for v.