If KE of a body increases by `300%`, by what `%` will the linear momentum of the body increase?

Options

A. `50%`
B. `100%`
C. `150%`
D. `300%`

Answer

D

Explanation

`KE = P^(2)//2m or P^(2) prop KE` (i)
`KE_(2) = KE_(2) + (300//100) KE_(1) = 4KE_(1)`
From (i) `(P_(2))/(P_(1)) = sqrt((KE_(2))/(KE_(1))) = sqrt((4KE_(1))/(KE_(1))) = 2`
It mean momentum becomes twice, hence increase in momentum is `100%`