A light body `A` and a heavy `B` have equal linear momentum. Then the `KE` of the body `A` is

Options

A. equal to that of `B`
B. greater then that of `B`
C. smaller then that of `B`
D. zero

Answer

B

Explanation

`m_(1) v_(1) and m_(2) v_(2)` and `m_(2) v_(2) and (K_(1))/(K_(2)) = (m_(1)v_(1)^(2))/(m_(2) v_(2)^(2)) = (m_(2))/(m_(1))`
As `m_(1) lt m_(2) :. K_(1) lt K_(2)`