The kinetic energy of partical moving along a circule of radius `R` depends upon the distance covered `S` and given by `K = aS` where `a` is a constant. The the force acting on the partical is

Options

A. constant
B. proportional to `v`
C. proportional to `v^(2)`
D. inversely proportional to `v`

Answer

D

Explanation

` KE prop x rArr KE =Cx rArr (1)/(2) mv^(2) =Cx`
`(1)/(2) m2v(dv)/(dt) =C(dx)/(dt) rArr mv(dv)/(dt) =Cv`
` m(dv)/(dt) = rArr ma =C`
`rArr F=C rarr `constant.