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A long elastic spring is stretched by 2 ...

A long elastic spring is stretched by `2 cm` and its potential energy is `U`. If the spring is stretched by `10 cm`, the `PE` will be

A

`(U)/(5)`

B

`U`

C

`5U`

D

`25U`

Text Solution

Verified by Experts

The correct Answer is:
D
`U prop x^(2)`
`implies (U_(2))/(U_(1)) = ((x_(2))/(x_(1)))^(2) = ((0.1)/(0.02))^(2) = 25 :. U_(2) = 25U`
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