A ball moving with velocity `2 ms^(-1)` collides head on with another stationary ball of double the mass. If the coefficient of restitution is `0.5`, then their velocities (in `ms^(-1)`) after colllision will be

Options

A. `0.1`
B. `1.1`
C. `1.05`
D. `0.2`

Explanation

To solve the problem, we will use the principles of conservation of momentum and the coefficient of restitution. Let's break it down step-by-step.

### Step 1: Define the variables
- Let the mass of the first ball be \( m \) and its initial velocity \( v_1 = 2 \, \text{m/s} \).
- The second ball has a mass of \( 2m \) and is initially at rest, so its initial velocity \( v_2 = 0 \, \text{m/s} \).
- After the collision, let the velocities of the first and second balls be \( u_1 \) and \( u_2 \) respectively.

### Step 2: Apply conservation of momentum
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