A uniform force of (3 hati + hatj) newto...

A uniform force of `(3 hati + hatj)` newton acts on a partical of mass `2 kg`. Hence the partical is displaced from position `(2 hati + hatk)` metre to possion `(4 hati + 3 hatj - hatk)` meters. The work done by the force on the partical is

`9 J`

`6 J`

`13 J`

`15 J`

Text Solution

Verified by Experts

Applied force `vecF = 3hati + hatj`
Displacement `vecS = vecr_(2) - vecr_(1) = 2 hati + 3 hatj - 2 hatk`
Hence work done `W = vecF. vecS = 6 + 3 +0 = 9 J`

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