On a friction surface a block a mass `M` moving at speed `v` collides elastic with another block of same mass `M` which is initially at rest . After collision the first block moves at an angle `theta` to its initial direction and has a speed `(v)/(3)`. The second block's speed after the collision is

Options

A. `(sqrt(3))/(2) v`
B. `(2 sqrt(2))/(3) v`
C. `(3)/(4) v`
D. `(3)/(sqrt2) v`

Explanation

To solve the problem, we will use the principles of conservation of momentum and conservation of energy, as the collision is elastic.

### Step 1: Understand the Initial Conditions
We have two blocks of mass \( M \):
- Block 1 is moving with speed \( v \).
- Block 2 is at rest (speed = 0).

### Step 2: Apply Conservation of Momentum
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