If `v` be the instantaneous velocity of the body dropped from the top of a power, when it is located at height `h`, then which of the following remains constant?

Options

A. `gh + v^(2)`
B. `gh + (v^(2))/(2)`
C. `gh - (v^(2))/(2)`
D. `gh - v^(2)`

Explanation

`KE + PE = constant implies (1)/(2) mv^(2) + mgh = C`
`implies (v^(2))/(2) + gh = ( C)/(m) = constant`