Water is flowing in a river at `2 ms^(-1)`. The river is `50 m` wide and has an average depth of `5 m`. The power available from the current in the river is (Density of water `= 1000 kg m^(3)`

Options

A. `0.5 MW`
B. `1 MW`
C. `1.5 MW`
D. `2 MW`

Explanation

To find the power available from the current in the river, we can follow these steps:

### Step 1: Calculate the Cross-Sectional Area of the River
The cross-sectional area \( A \) of the river can be calculated using the formula:
\[ A = \text{width} \times \text{depth} \]
Given that the width of the river is \( 50 \, m \) and the average depth is \( 5 \, m \):
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