Two identical balls `A` and `B` are released from the position shown in Fig. They collide elastically with each other on the horizontal portion. The ratio of heights attained by `A` and `B` after collision is (neglect friction)

Options

A. `1:4`
B. `2:1`
C. `4:13`
D. `2:5`

Explanation

After collision the balls exchange theirt velocity their velocities, i.e.,
`v_(A) = sqrt(2gh) and v_(B) = sqrt(2g(4h)) = 2 sqrt(2gh)`

Height attained by `A` will be : `h_(A) = (v_(A)^(2))/(2g) = h`
But path of `B` will be first straight line and then parabolic as shown in figure. After calculation we can shown that : `h_(B) = (13)/(4) h and (h_(A))/(h_(B)) = (4)/(13)`