The depth at which the value of acceleration due to gravity is `1/n` times the value at the surface, is (R=radius of the earth)

Options

A. `R/n`
B. `R((n-1)/n)`
C. `R/(n^(2))`
D. `R(n/(n+1))`

Answer

B

Explanation

`g'=g(1-d/R)implies g/n=g(1-d/R)`
`implies d/R=1-1/nimplies d=((n-1)/n)R`