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A man weighs 80 kg on the surface of ear...

A man weighs `80 kg` on the surface of earth of radius `r`. At what height above the surface of earth his weight will be `40 kg`?

A

`R/2`

B

`sqrt(2)R`

C

`(sqrt(2)-1)R`

D

`(sqrt(2)+1)R`

Text Solution

Verified by Experts

The correct Answer is:
C
`40/80=(R^(2))/((R+h)^(2))`
`=sqrt(2)R=R+h`
`h=(sqrt(2)-1)R`
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