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Two spherical soap bubbles of radii r1 a...

Two spherical soap bubbles of radii `r_1` and `r_2` in vacuume collapse under isothermal condition. The resulting bubble has radius `R` such that

A

`R=r_1+r_2`

B

`R=(r_1+r_2)^((1)/(2))`

C

`R=sqrt(r_1^2+r_2^2)`

D

`R=[(r_2r_2(r_1+r_2)]`

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The correct Answer is:
To solve the problem of two spherical soap bubbles collapsing under isothermal conditions to form a new bubble, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Initial Conditions**: We have two soap bubbles with radii \( r_1 \) and \( r_2 \) in a vacuum. The pressure inside each bubble is influenced by the surface tension of the soap film. 2. **Pressure Inside the Bubbles**: The pressure inside a soap bubble is given by the formula: \[ P = \frac{4S}{r} \] where \( S \) is the surface tension and \( r \) is the radius of the bubble. Therefore, the pressures for the two bubbles are: \[ P_1 = \frac{4S}{r_1} \quad \text{and} \quad P_2 = \frac{4S}{r_2} \] 3. **Volume of the Bubbles**: The volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi r^3 \] Thus, the volumes of the two bubbles are: \[ V_1 = \frac{4}{3} \pi r_1^3 \quad \text{and} \quad V_2 = \frac{4}{3} \pi r_2^3 \] 4. **Applying the Isothermal Condition**: Under isothermal conditions, the product of pressure and volume for the two initial bubbles equals the product of pressure and volume for the final bubble: \[ P_1 V_1 + P_2 V_2 = P_f V_f \] where \( P_f \) is the pressure of the final bubble and \( V_f \) is its volume. 5. **Volume of the Final Bubble**: The volume of the resulting bubble with radius \( R \) is: \[ V_f = \frac{4}{3} \pi R^3 \] 6. **Substituting the Pressures and Volumes**: Substitute the expressions for pressures and volumes into the equation: \[ \left(\frac{4S}{r_1}\right) \left(\frac{4}{3} \pi r_1^3\right) + \left(\frac{4S}{r_2}\right) \left(\frac{4}{3} \pi r_2^3\right) = \left(\frac{4S}{R}\right) \left(\frac{4}{3} \pi R^3\right) \] 7. **Simplifying the Equation**: Cancel out common terms (like \( \frac{4}{3} \pi \) and \( 4S \)): \[ \frac{r_1^3}{r_1} + \frac{r_2^3}{r_2} = \frac{R^3}{R} \] This simplifies to: \[ r_1^2 + r_2^2 = R^2 \] 8. **Final Expression for R**: Taking the square root of both sides gives: \[ R = \sqrt{r_1^2 + r_2^2} \] ### Final Answer: The radius \( R \) of the resulting bubble is: \[ R = \sqrt{r_1^2 + r_2^2} \]

To solve the problem of two spherical soap bubbles collapsing under isothermal conditions to form a new bubble, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Initial Conditions**: We have two soap bubbles with radii \( r_1 \) and \( r_2 \) in a vacuum. The pressure inside each bubble is influenced by the surface tension of the soap film. 2. **Pressure Inside the Bubbles**: ...
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