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The excess pressure due to surface tensi...

The excess pressure due to surface tension inside a spherical drop is `6 units`. If eight such drops combine, then the excess pressure due to surface tension inside the larger drop is

A

3 units

B

6 units

C

12 units

D

48 units

Text Solution

Verified by Experts

The correct Answer is:
A
`8xx(4)/(3)pir^3=(4)/(3)piR^3`,`R=2r`
`(2sigma)/(P)=(2xx2sigma)/(p)` or `P=(p)/(2)=(6)/(2)units=3units`
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Knowledge Check

  • The excess pressure due to surface tension inside a spherical drop is 6 . If 27 such drops coalesce, the excess pressure inside the new drop is

    A
    ` 6 N//m^(2)`
    B
    ` 18 N//m^(2)`
    C
    `12 N//m^(2)`
    D
    `2 N//m^(2)`

  • The excess pressure due to surface tension in a spherical liquid drop of radius r is directly proportional to

    A
    r
    B
    `r^(2)`
    C
    `r^(-1)`
    D
    `r^(-2)`

  • The excess of pressure, due to surface tension, on a spherical liquid drop of radius 'R' is proportional to

    A
    `R^(-1)`
    B
    R
    C
    `R^(-2)`
    D
    `R^(2)`

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