A capillary of the shape as shown is dipped in a liquid. Contact angle between the liquid and the capillary is `0^@` and effect of liquid inside the mexiscus is to be neglected. `T` is surface tension of the liquid, `r` is radius of the meniscus, `g` is acceleration due to gravity and `rho` is density of the liquid then height `h` in equilibrium is:

Options

A. greater than `(2T)/(rrhog)`
B. equal to `(2T)/(rrhog)`
C. less than `(2T)/(rrhog)`
D. of any value depending upon act.

Answer

B

Explanation

`2pirT=pir^2` `rhoghimpliesh=(2T)/(rrhog)`
But weight of liquid in tapered tube is more than uniform tube of radius `r`, then the order to balance `hlth_1`
`hlt(2T)/(rrhog)`