Coefficient of vilocity of water =0.01 ...

Coefficient of vilocity of water `=0.01` poise, density of water `=1 g cm ^(-3)`. Then the maximum velocity with which water can flow through a capillary tube of radius `0.05 cm`, without turbulent flow setting in, is

A

`2cms^-1`

B

`20cms^-1`

C

`200cms^-1`

D

`2000cms^-1`

Text Solution

Verified by Experts

The correct Answer is:

C

`v_c=(2000xx0.01)/(1xx2xx0.05)cms^-1=200cms^-1`

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