The metal cube of side 10 cm is subjected to a shearing stress of `10^(4)Nm^-2`. The modulus of rigidiy if the top of the cube is displaced by 0.05 cm with respect to its bottom is

Options

A. `2xx10^6Nm^-2`
B. `105Nm^-2`
C. `1xx10^(7)Nm^-2`
D. `4xx10^5Nm^-2`

Answer

A

Explanation

Here, `l=10cm`,`trianglel=0.05cm`
Shearing stress`=10^4Nm^-2`
`eta=(sheari ng stress)/(sheari ng strai n)=(10^4))/(0.005)=2xx10^6Nm^-2`