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A wire suspended vertically from one of itsends is strached by attached a weight of `200 N` to the lower end . The weight streches the wire by `1 mm` . Then the elastic energy stored in the wire is

A

`0.1J`

B

`0.2J`

C

`10J`

D

`20`

Text Solution

Verified by Experts

The correct Answer is:
A
`U=(1)/(2)xxFxxl=(1)/(2)xx200xx10^-3=0.1J`
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