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A cord of mass m length L, area of cross...

A cord of mass m length L, area of cross section A and Young's modulus y is hanging from a ceiling with the help of a rigid support. The elogation developed in the wire due to its own weight is

A

zero

B

`(mgL)/(AY)`

C

`(mgL)/(2AY)`

D

`(2mgL)/(AY)`

Text Solution

Verified by Experts

The correct Answer is:
C

Since the entire weight `mg` of the wire is concentrated at it at its centre of mass which lies at the geometrical centre
of the wire. So the effective original length of the wire is `(L)/(2)`. According to Hooke's Law
`Y=(stress)/(strai n)`
`Y=((mg)/(A))/((triangleL)/((L)/(2)))impliestriangleL=(mgL)/(2AY)`
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