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If layer thickness L(2) is 1.4 cm, then ...

If layer thickness `L_(2)` is `1.4 cm`, then its thermal conductivity `K_(2)` will have value `("in " W//mK)`

A

`2 xx 10^(-2)`

B

`2 xx 10^(-3)`

C

`4 xx 10^(-2)`

D

`4 xx 10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(Delta Q)/(DeltaT)|_("layer" 2)` = `(Delta Q)/(Delta T)|_("layer" 4)`
`rArr (0.06xxAxx5)/(1.5xx10^(-2)) = (K_(2)xxAxx14)/(1.4xx10(-2))`
`rArr K_(2) = 0.02 W//mK`.
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