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A piece of ice falls from a height h so ...

A piece of ice falls from a height `h` so that it melts completely. Only one-quarter of the heat produced is absobed by the ice and all energy of ice gets converted into heat during its fall. The value of `h` is
[Latent heat of ice is `3.4 xx 10^(5) J//kg` and `g = 10 N//kg`]

A

`34 km`

B

`544 km`

C

`136 km`

D

`68 km`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the height \( h \) from which the piece of ice falls, given that it melts completely upon falling and that only one-quarter of the heat produced is absorbed by the ice. ### Step-by-Step Solution: 1. **Identify the energy conversion**: When the ice falls from a height \( h \), its gravitational potential energy (PE) is converted into heat energy (Q) when it reaches the ground. The potential energy of the ice at height \( h \) is given by: \[ PE = mgh \] where \( m \) is the mass of the ice, \( g \) is the acceleration due to gravity, and \( h \) is the height. 2. **Heat absorbed by the ice**: According to the problem, only one-quarter of the heat produced during the fall is absorbed by the ice. Therefore, the heat absorbed by the ice is: \[ Q = \frac{1}{4} \times PE = \frac{1}{4} \times mgh \] 3. **Heat required to melt the ice**: The heat required to completely melt the ice is given by the formula: \[ Q_{melt} = mL \] where \( L \) is the latent heat of fusion of ice. Given \( L = 3.4 \times 10^5 \, \text{J/kg} \), we can write: \[ Q_{melt} = m \times 3.4 \times 10^5 \] 4. **Setting the equations equal**: Since the heat absorbed by the ice is equal to the heat required to melt it, we can set the two equations equal to each other: \[ \frac{1}{4} mgh = m \times 3.4 \times 10^5 \] 5. **Canceling mass \( m \)**: We can cancel \( m \) from both sides of the equation (assuming \( m \neq 0 \)): \[ \frac{1}{4} gh = 3.4 \times 10^5 \] 6. **Solving for height \( h \)**: Rearranging the equation to solve for \( h \): \[ h = \frac{4 \times 3.4 \times 10^5}{g} \] Substituting \( g = 10 \, \text{N/kg} \): \[ h = \frac{4 \times 3.4 \times 10^5}{10} = 1.36 \times 10^5 \, \text{m} \] 7. **Final conversion to kilometers**: To convert meters to kilometers: \[ h = 1.36 \times 10^5 \, \text{m} = 136 \, \text{km} \] ### Final Answer: The value of \( h \) is \( 136 \, \text{km} \).

To solve the problem, we need to find the height \( h \) from which the piece of ice falls, given that it melts completely upon falling and that only one-quarter of the heat produced is absorbed by the ice. ### Step-by-Step Solution: 1. **Identify the energy conversion**: When the ice falls from a height \( h \), its gravitational potential energy (PE) is converted into heat energy (Q) when it reaches the ground. The potential energy of the ice at height \( h \) is given by: \[ PE = mgh ...
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A piece of ice falls from a hight h so that it melts completely. Only one quarter of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of h is : (Latent heat of ice is 3.4xx10^(5) j//kg and g=10N//kg )

A piece of ice falls from a heighth so that it melts completely. Only one-quarter of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of height from which ice fall . [Latent heat of ice is 3.4 xx 10^(5) J//kg and g = 10 N/kg]

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