A black body is at a temperature of `5760 K`. The energy of radiation emitted by the body at wavelength `250 nm` is `U_(1)` at wavelength `500 nm` is `U_(2)` and that at `1000 nm` is `U_(3)`. Wien's consant, `b = 2.88 xx 10^(6) nmK`. Which of the following is correct?

Options

A. `U_(1) = 0`
B. `U_(3) = 0`
C. `U_(1) gt U_(2)`
D. `U_(2) gt U_(1)`

Answer

D

Explanation

Wein's displacement law, `lambda_(m)T = b`
`rArr lambda_(m) = b/T = (2.88xx10^(6))/(2880) = 1000nm`
Energy distribution with wavelength will be as follows

From the graph it is clear that `U_(2) gt U_(1)`.