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A string of length 2 m is fixed at both ...

A string of length 2 m is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of 500 Hz then the waves wouldf travel on it is with a velocity of

A

`125 m//s`

B

`25m//s`

C

`500 m//s`

D

`1000 m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
For string `lamda=(2l)/(p)`
where `p=` No. of loops`=`Order of vibration
Hence for fourth mode `p=4implieslamda=(l)/(2)`
hence `v=nlamda=500xx(2)/(2)=500Hz`
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