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The first overtone of a stretched string...

The first overtone of a stretched string of given length is 320 Hz. The first harmonic is

A

`320Hz`

B

`640Hz`

C

`160Hz`

D

`480Hz`

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The correct Answer is:
To find the first harmonic (fundamental frequency) of a stretched string given that the first overtone is 320 Hz, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between harmonics and overtones**: - The first harmonic (fundamental frequency) is denoted as \( f \). - The first overtone corresponds to the second harmonic, which is \( 2f \). 2. **Use the information given**: - We know that the first overtone is 320 Hz. Since the first overtone is the second harmonic, we can write: \[ 2f = 320 \text{ Hz} \] 3. **Solve for the fundamental frequency**: - To find the fundamental frequency \( f \), we can rearrange the equation: \[ f = \frac{320}{2} \] - Calculating this gives: \[ f = 160 \text{ Hz} \] 4. **Conclusion**: - Therefore, the first harmonic (fundamental frequency) of the stretched string is 160 Hz. ### Final Answer: The first harmonic is **160 Hz**. ---

To find the first harmonic (fundamental frequency) of a stretched string given that the first overtone is 320 Hz, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between harmonics and overtones**: - The first harmonic (fundamental frequency) is denoted as \( f \). - The first overtone corresponds to the second harmonic, which is \( 2f \). ...
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