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A wire having a linear mass density 5.0x...

A wire having a linear mass density `5.0xx10^(3) kg//m` is stretched between two rigid supports with tension of 450 N. The wire resonates at a frequency of `420 Hz`. The next higher frequency at which the same wire resonates is ` 480 N`. The length of the wire is

A

`2.0 m`

B

`2.1 m`

C

`2.5 m`

D

`3 m`

Text Solution

Verified by Experts

The correct Answer is:
B
Two consecutive frequencies are 420 Hz and 480 Hz. So the fundamental frequency will be `60 Hz`.
`60=(1)/(2xxl)sqrt((450)/(5xx10^-3))impliesl=2.1m`
Hence (b).
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