The length of the wire shown in Fig. Between the pulley and fixed support is `1.5m` and mass is `12.0g` the frequency of vibration with which the wire vibrate two loops leaving the middle point of the wire between the pulleys at rest is

Options

A. `10Hz`
B. `30Hz`
C. `100Hz`
D. `70Hz`

Answer

C

Explanation

`f=(2)/(2l)sqrt((T)/(mu))` or `f=(1)/(l)sqrt((T)/(mu))`
or `f=sqrt((Tl)/(Ml^(2))` or `f=sqrt((T)/(Ml))`
or `v=sqrt((18xx10xx1000)/(12xx1.5))Hz=100Hz`.