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A string of length 1.5 m with its two en...

A string of length 1.5 m with its two ends clamped is vibrating in fundamental mode. Amplitude at the centre of the string is 4 mm. Minimum distance between the two points having amplitude 2 mm is:

A

`1m`

B

`75cm`

C

`60cm`

D

`50cm`

Text Solution

Verified by Experts

The correct Answer is:
A

Equation of standing wave
`y=Asinkxcosomegat`
`y=A` as amplitude is 2A
`A=2Asinkx`
`(2pi)/(lamda)x=(pi)/(6)impliesx_1=(1)/(4)m`
and `(2pi)/(lamda).x=(pi)/(2)+(pi)/(3)`
`impliesx_1=1.25mimpliesx_2-x_1=1m`
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