In the above question the ratio of the first overtone of A to first overtone of B is :

Options

A. `5:6`
B. `6:5`
C. `10:9`
D. `9:10`

Answer

C

Explanation

First overtone of open pipe `=(2v)/(2l_1)` , First overtone of closed pipe `=(3v)/(4l_2)`
Required ratio `implies(v)/(l_1)xx(4l_2)/(3v)=(4)/(3)xx(l_2)/(l_1)`
From above question `(l_2)/(l_1)=(5)/(6)`
So ratio will be `(4)/(3)xx(5)/(6)=(10)/(9)=10:9` Hence (c ).