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In expressing sound intensity we take 10...

In expressing sound intensity we take `10^(-12)(W)/(m^2)` as the reference level. For ordinary conversation the intensity level is about `10^-6(W)/(m^2)`. Expressed in decibel, this is

A

`10^(6)`

B

`6`

C

`60`

D

`log_(e)(10^6)`

Text Solution

Verified by Experts

The correct Answer is:
C
Bel is `log_(10)((I)/(I_0))`. Here it is 6. In decibel It is 60.
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