A transverse sinusoidal wave of amplitude `a`, wavelength `lambda` and frequency `f` is travelling on a stretched string. The maximum speed of any point in the string is `v//10`, where `v` is the speed of propagation of the wave. If `a = 10^(-3)m` and `v = 10ms^(-1)`, then `lambda` and `f` are given by

Options

A. `y=2pixx10^(-2)m`
B. `lamda=10^(-3)m`
C. `n=(10^(3))/(2pi)Hz`
D. `n=10^4Hz`

Answer

A, C

Explanation

`v_(max)=aomega=(v)/(10)=(10)/(10)=1m//s`
`impliesaomega=axx2pin=1`
`rArr =(10^3)/(2pi)" "( :. A =10^(-3) m)`
Since `v=nlamdaimplieslamda=(v)/(n)=(10)/(10^(3)//2pi)=2pixx10^(-2)m`.