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A metal wire of linear mass density of `9.8g//m` is stretched with a tension of `10 kg-wt` between two rigid support `1meter` apart. The wire passes at its middle point between the poles of a permanent magnet, and it vibrates in resonance when carrying an alternating current of frequency `n`. the frequency `n` of the alternating source is

A

25 Hz

B

50 Hz

C

100 Hz

D

200 Hz

Text Solution

Verified by Experts

The correct Answer is:
B
In condition of resonance frequency of a.c. will be equal to natural frequency of wire
`n=(1)/(2l)sqrt((T)/(m))=(1)/(2xx1)sqrt((10xx9.8)/(9.8xx10^-3))=(100)/(2)=50`Hz
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