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Dimension of resistance in an elecatrica...

Dimension of resistance in an elecatrical circuit, in terms of dimension of mass `M`, of length `L`, of time `T`, and of current `I`, would be

A

`[ML^(2)T^(3)I^(-I)]`

B

`[ML^(2)T^(2)]`

C

`[ML^(2)L^(-1)]`

D

`[ML^(2)T^(3)]`

Text Solution

Verified by Experts

The correct Answer is:
D

Resistance
`R=("potential di fference")/("Current")=V/i=W/(qi)`
(`:.` Potential difference is equal to work done per unit charge)
So, Dimension of `R`
`=(["Dimension of work"])/(["Dimension of charge"]["Dimension of current"])`
`=([ML^(2)T^(-2)])/([IT][I])=[ML^(2)T^(-3)I^(-2)]`
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