Home
Class 11
PHYSICS
A block has been placed on an inclined p...

A block has been placed on an inclined plane with the slope angle `theta`. Block slide down the plane at constant speed. The cofficient of Kinetic friction is equal to

A

`sin theta`

B

`cos theta`

C

`g`

D

`tan theta`

Text Solution

Verified by Experts

The correct Answer is:
D
When a block slides down the plane with a constant speed, then the inclination of the plane is equal to angle of repose `(theta)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOCK TEST

    A2Z|Exercise General Kinematics|30 Videos

  • MOCK TEST

    A2Z|Exercise Motion With Constant Acceleration|15 Videos

  • KINETIC THEORY OF GASES AND THERMODYNAMICS

    A2Z|Exercise Chapter Test|29 Videos

  • MOTION IN TWO DIMENSION

    A2Z|Exercise Chapter Test|29 Videos

Similar Questions

Explore conceptually related problems

A block is placed on an inclined plane. The angle of inclination of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is

A block of mass m moves with constant speed down the inclined plane of inclination theta . Find the coefficient of kinetic friction.

Knowledge Check

  • A block has been placed on an inclined plane . The slope angle of theta of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

    A
    sin `theta`
    B
    cos `theta`
    C
    g
    D
    tan `theta`

  • A block of mass 10 kg is placed on an inclined plane when the angle of inclination is 30^(@) . The block just begins to slide down the plane. The force of static friction is

    A
    10 kg wt
    B
    89 kg w
    C
    49 kg wt
    D
    5 kg wt

  • A block is at rest on an inclined plane making an angle alpha with the horizontal . As the angle alpha of the incline is increased the block starts slipping when the angle of inclination becomes theta . The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle theta to the horizontal. Then the coefficient of friction is equal to

    A
    `sin theta`
    B
    `cos theta`
    C
    `tan theta`
    D
    Independent of `theta`

    • Similar Questions

    Explore conceptually related problems

    A block takes a twice as much time to slide down a 45^(@) rough inclined plane as it takes to slide down a similar smooth , plane . The coefficient of friction is :

    A block sliding down on a rough 45^(@) inclined plane has half the velocity it would have been, the inclined plane is smooth. The coefficient of sliding friction between the block and the inclined plane is

    A block sliding down on a rough 45^(@) inclined planes has half the velocity it would have been, the inclined plane is smooth. The coefficient of sliding friction between the the block and the inclined plane is

    A block of mass m sliding down an inclined at constant speed is initial at a height h shown the ground as shown in the figure above . The coefficient of kinetic friction between the mass and the inclined is mu . If the mass constinues to slide down the inclined at a constant speed how much energy is displaced by friction by the time the mass reaches the bottom of the incline?

    A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is

    Home
    Profile