Given standard electrode potentials
`K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V`,
`Hg^(2+)|Hg=0.79V`
`Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V`
Arrange these metals in their increasing order of reducing power.

Given : K^(+)|K=-2.79V, Ag^(+)|Ag=0.80V, Hg^(2+)|Hg=0.79V, Mg^(2+)|Mg=-2.37V and Cr^(3+)|Cr=-0.74V . Arrange these metals in their increasing order of reducing power.

Given, the standard electrode potentials, K^+//K = -2.93 V, Ag^+//Ag = 0.80 V, Hg^(2+)//Hg =0.79 V, Mg^(2+)//Mg = - 2.37 V, Cr^(3+)//Cr = - 0.74 V Arrange these metals in their increasing order of reducing power.