An object is dropped from rest at a height of `150 m` and simultanously another object is dropped from rest at a height `100m`. What is the difference in their height after `2 s` if both the objects drop with same acceleration ? How does the difference in height vary with time ?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the motion of both objects
Both objects are dropped from rest, which means their initial velocity (u) is 0 m/s. They are under the influence of gravity, so they will accelerate downwards with an acceleration (a) of approximately 9.81 m/s².

### Step 2: Calculate the distance fallen by each object after 2 seconds
The formula for the distance (s) fallen under constant acceleration is given by:
\[ s = ut + \frac{1}{2} a t^2 \]
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