A scooter acquires a velocity of ` 36 km//h` in `10` seconds just after the start . Calculate the acceleration of the scooter.

Answer

`1m//s^(2)`

Explanation

Here, ` u = 0 , t = 10 s` , `v = 36 (km)/(h) = 10 m//s` , `a = ( v - u)/( t) = ( 10 - 0)/( 10) = 1 m//s^(2)`