The brakes applied to a car produce an acceleration of `6 m//s^(2)` in the opposite direction to the motion . If the car takes ` 2 s` to stop after the application of brakes , calculate the distance it travels during this time.

Answer

`12 m`

Explanation

Here , ` a= -6 m//s^(2) , v = 0 , t = 2 s, s = ?`
From ` v = u + at , 0 = u -6 xx2 , u = 12 m//s`
From ` v^(2) - u^(2) = 2 as , s = (v^(2) - u^(2))/( 2 a) = ( 0 - 12^(2))/( 2 xx (-6)) = 12 m`