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A body is thrown vertically upwards with...

A body is thrown vertically upwards with a velocity of `98 m//s`. If `g = 9.8 m//s^(2)`, when will it reach its highest point ? What will be its maximum height ?

Text Solution

Verified by Experts

Here, `u = 98 m//s, g = -9.8 m//s^(2), t = ? h = ?`
From `v = u + at`
`0 = 98 - 9.8 t, t = (98)/(9.8) = 10 s`
From `v^(2) - u^(2) = 2 as`
`0 - (98)^(2) = 2(-9.8)h`
`h = (-98 xx 98)/(-2 xx 9.8) = 490 m`
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