The speed time graph of a body is as shown in Figure. Calculate
(i) acceleration of body, (ii) retardation of body, (iii) total distance travelled by the body.

Explanation

(i) Acceleration of body (from portion `OA`), Fig.
`= ("change in vel.")/("time taken") = ((10 - 0))/(5) = 2 m//s^(2)`.
(ii) Retardation of body (from portion `BC`), Fig.
`= ("change in velocity")/("time taken") = ((0 - 10))/(16 - 10) = - 1.67 m//s^(2)`.
Total distance travelled = Area under the graph `OABC`, Fig.
`= (10 xx 5)/(2) + 10 xx 5 + (10 xx 6)/(2) = 105 m`