Suppose a boy is enjoying a ride on a merry-go-round which is moving with a constant speed of `10 ms^(-1)`. It implies that the boy is

Options

A. at rest
B. moving with no acceleration
C. in acceleration motion
D. moving with uniform velocity

Explanation

To solve the question, "Suppose a boy is enjoying a ride on a merry-go-round which is moving with a constant speed of 10 m/s. It implies that the boy is...", we need to analyze the situation carefully.

### Step-by-Step Solution:

1. **Understanding the Motion**:
The boy is on a merry-go-round that is moving in a circular path at a constant speed of 10 m/s.

2. **Identifying Speed and Velocity**:
- Speed is a scalar quantity that refers to how fast an object is moving, which in this case is constant at 10 m/s.
- Velocity is a vector quantity that includes both speed and direction. Since the boy is moving in a circle, although the speed is constant, the direction of his velocity is continuously changing.

3. **Acceleration in Circular Motion**:
- Even though the speed is constant, the change in direction means that the boy is experiencing centripetal acceleration. This acceleration is directed towards the center of the circular path.
- The formula for centripetal acceleration (a_c) is given by \( a_c = \frac{v^2}{r} \), where \( v \) is the speed and \( r \) is the radius of the circular path.

4. **Conclusion**:
- Since the boy is moving in a circular path with a constant speed but changing direction, he is in a state of uniform circular motion.
- This implies that the boy is experiencing acceleration due to the change in direction of his velocity, even though his speed remains constant.

### Final Answer:
The boy is in uniform circular motion, which implies that he is experiencing centripetal acceleration.

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