A ball thrown vertically upwards with a speed of `19.6 ms^(-1)` from the top of a tower returns to earth in `6 s`. Calculate the height of the tower.

A ball throuwn vertically upwards with a speed of 19.6ms^(-1) from the top of a tower returns to the earth in 6s. Find the height of the tower.

A stone is thrown vertically upwards with an initial speed u from the top of a tower, reaches the ground with a speed 3 u . The height of the tower is :

A stone is thrown vertically upwards from the top of a building, with a speed of 14.7m/s. if it returns to the earth in 8s, calculate the height of the building.

A ball is thrown vertically upwards with a speed of 10 m//s from the top of a tower 200 m height and another is thrown vertically downwards with the same speed simultaneously. The time difference between them on reaching the ground is (g=10 m//s^(2))

A ball is thrown upwards with speed v from the top of a tower and it reaches the ground with speed 3v .The height of the tower is

A stone thrown upward with a speed u from the top of a tower reaches the ground with a velocity 4u. The height of the tower is

A ball is thrown downwards with a speed of 20 ms^(–1) from top of a building 150m high and simultaneously another ball is thrown vertically upwards with a speed of 30 ms^(–1) from the foot of the building. Find the time after which both the balls will meet - (g = 10 ms^(–2))

A ball is projected vertically upwards with a velocity of 25ms^(-1) from the bottom of a tower. A boy who is standing at the top of a tower is unable to catch the ball when it passes him in the upward direction. But the ball again reaches him after 3 sec when it is falling. Now the boy catches it then the height of the tower is (g=10ms^(-2))