A stone of `1kg` is thrown with a velocity of `20 ms^(-1)` across the frozen surface of lake and comes to rest after travelling a distance of `50m`. What is the force of friction between the stone and the ice?

Explanation

To find the force of friction between the stone and the ice, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Mass of the stone (m) = 1 kg
- Initial velocity (u) = 20 m/s
- Final velocity (v) = 0 m/s (since the stone comes to rest)
...