How much momentum will a dumb-bell of mass `10kg` transfer to the floor if it falls a height of `80 cm`? Take its downward acceleration to be `10 m//s^(2)`.

Explanation

Here, `m = 10kg, s= 80cm=0.8m, a= 10ms^(-2)`
`u=0, v=?, p=?`
From `v^(2)-u^(2)=2 as, v^(2)-0 = 2xx10xx0.8= 16` or `v= sqrt(16) = 4m//s`
momentum transferred, `p= mv= 10xx4= 40kgm//s`